Let f ( x ) = 1 − ( x 2 ) where the square root is to be taken positive, then

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Let $f(x)=1-\sqrt{\left(x^{2}\right)}$ where the square root is to be taken positive, then

MathematicsApplication of DerivativesWBJEEWBJEE 2020

Options:

A $f$ has no extrema at $x=0$
B $f$ has minima at $x=0$
C $f$ has maxima at $x=0$
D $\mathrm{f}^{\prime}$ exists at 0

Solution:

1505 Upvotes Verified Answer

The correct answer is: $f$ has maxima at $x=0$

Hint:
$f(x)=1-|x|, f$ has maxima at $x=0$

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