Let f ( x ) be a polynomial of degree 5 with leading coefficient unity such that f ( 1 ) = 5 , f ( 2 ) = 4 , f ( 3 ) = 3 , f ( 4 ) = 2 , f ( 5 ) = 1 . Then f ( 6 ) is equal to :

Question

Let f ( x ) be a polynomial of degree 5 with leading coefficient unity such that f ( 1 ) = 5 , f ( 2 ) = 4 , f ( 3 ) = 3 , f ( 4 ) = 2 , f ( 5 ) = 1 . Then f ( 6 ) is equal to :, 0, 24, 120, 720

MARKS App · Accepted Answer

​ f ( x ) + x − 6 = ( x − 1 ) ( x − 2 ) ( x − 3 ) ( x − 4 ) ( x − 5 ) ⇒ f ( 6 ) = 120 ​

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