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Let $N$ denote the set of all non-negative integers and $Z$ denote the set of all integers. The function $f: Z \rightarrow N$ given by
$f(x)=|x|$ is:
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$f(x)=|x|$ is:
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Onto but not one-one
$f: \mathrm{Z} \rightarrow \mathrm{N}$ and $f(\mathrm{x})=|\mathrm{x}|$
When we draw a parallel line to $\mathrm{x}$ -axis. It cuts the curve into more than one point. Therefore, $f(\mathrm{x})=|\mathrm{x}|$ is not one-one. but onto
When we draw a parallel line to $\mathrm{x}$ -axis. It cuts the curve into more than one point. Therefore, $f(\mathrm{x})=|\mathrm{x}|$ is not one-one. but onto
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