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Let $\mathrm{P}$ be an interior point of a triangle $\mathrm{ABC}$. Let $\mathrm{Q}$ and $\mathrm{R}$ be the reflections of $\mathrm{P}$ in $\mathrm{AB}$ and $\mathrm{AC}$, respectively. IF $\mathrm{Q}, \mathrm{A}, \mathrm{R}$ are collinear then $\angle A$ equals.
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Verified Answer
The correct answer is:
$90^{\circ}$

So from Diagram
$$
\begin{array}{l}
\theta+\theta+\phi+\phi=180^{\circ} \\
\angle \mathrm{A}=\theta+\phi=90^{\circ}
\end{array}
$$
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