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Let $S_{n}$ denote the sum of the $n$ terms of an $\mathrm{AP}$ and $3 \mathrm{~S}_{\mathrm{n}}=\mathrm{S}_{2 \mathrm{n}}$.
What is $\mathrm{S}_{3 \mathrm{n}}=\mathrm{S}_{2 \mathrm{n}}$ equal to?
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What is $\mathrm{S}_{3 \mathrm{n}}=\mathrm{S}_{2 \mathrm{n}}$ equal to?
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The correct answer is:
$2: 1$
From explanation $\frac{\mathrm{S}_{3 \mathrm{n}}}{\mathrm{S}_{2 \mathrm{n}}}=\frac{6 \mathrm{n}^{2} \mathrm{~d}}{3 \mathrm{n}^{2} \mathrm{~d}}=\frac{2}{1}=2: 1$
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