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Let sets $R$ and $T$ be defined as
$R=\{x \in Z \mid x$ is divisible by 2$\}$
$T=\{x \in Z \mid x$ is divisible by 6$\}$. Then $T \subset R$
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$R=\{x \in Z \mid x$ is divisible by 2$\}$
$T=\{x \in Z \mid x$ is divisible by 6$\}$. Then $T \subset R$
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