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Question: Answered & Verified by Expert
Let the coordinates of the points $\mathrm{A}, \mathrm{B}, \mathrm{C}$ be $(1,8,4)$, $(0,-11,4)$ and $(2,-3,1)$ respectively. What are the coordinates of the point $D$ which is the foot of the perpendicular from $\mathrm{A}$ on $\mathrm{BC}$ ?
MathematicsThree Dimensional GeometryNDANDA 2018 (Phase 1)
Options:
  • A $(3,4,-2)$
  • B $(4,-2,5)$
  • C $(4,5,-2)$
  • D $(2,4,5)$
Solution:
1745 Upvotes Verified Answer
The correct answer is: $(4,5,-2)$
$\mathrm{A}(1,8,4), \mathrm{B}(0,-11,4), \mathrm{C}(2,-3,1)$
Let $\mathrm{D}=(\alpha, \beta, \gamma)$


Direction ratios of $\mathrm{BC}=\left(\mathrm{x}_{2}-\mathrm{x}_{1}, \mathrm{y}_{2}-\mathrm{y}_{1}, \mathrm{z}_{2}-\mathrm{z}_{1}\right)$
Let, $(\mathrm{a}, \mathrm{b}, \mathrm{c})=(2,8,-3)$
Direction 1 Let (a'. Since, $\mathrm{AD}$ is perpendicular to $\mathrm{BC}$,
e find option (c) is correct.
know, the equation of plane passing through 3

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