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Question: Answered & Verified by Expert
Let the pairs $\vec{a}, \vec{b}$ and $\vec{c}, \vec{d}$ each determine a plane. Then the planes are parallel if
MathematicsQuadratic EquationVITEEEVITEEE 2007
Options:
  • A $(\vec{a} \times \vec{c}) \times(\vec{b} \times \vec{d})=\overrightarrow{0}$
  • B $(\vec{a} \times \vec{c}) \cdot(\vec{b} \times \vec{d})=0$
  • C $(\vec{a} \times \vec{b}) \times(\vec{c} \times \vec{d})=\overrightarrow{0}$
  • D $(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}) \cdot(\overrightarrow{\mathrm{c}} \times \overrightarrow{\mathrm{d}})=\overrightarrow{0}$
Solution:
1543 Upvotes Verified Answer
The correct answer is: $(\vec{a} \times \vec{b}) \times(\vec{c} \times \vec{d})=\overrightarrow{0}$
Since $\vec{a}$ and $\vec{b}$ are coplanar, therefore $\vec{a} \times \vec{b}$ is a vector perpendicular to the plane containing $\overrightarrow{\mathrm{a}}$ and $\overrightarrow{\mathrm{b}}$. Similarly $\overrightarrow{\mathrm{c}} \times \overrightarrow{\mathrm{d}}$ is a vector perpendicular to the plane containing $\overrightarrow{\mathrm{c}}$ and $\overrightarrow{\mathrm{d}}$. Thus, the two planes will be parallel if their normals i.e. $\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}$ and $\overrightarrow{\mathrm{c}} \times \overrightarrow{\mathrm{d}}$ are parallel. $\Rightarrow(\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}) \times(\overrightarrow{\mathrm{c}} \times \overrightarrow{\mathrm{d}})=0$

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