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Question: Answered & Verified by Expert
Let the points of intersections of the lines x-y+1=0, x-2y+3=0 and 2x-5y+11=0 are the mid points of the sides of a triangle ABC. Then the area of the triangle ABC is
MathematicsStraight LinesJEE MainJEE Main 2021 (01 Sep Shift 2)
Solution:
2367 Upvotes Verified Answer
The correct answer is: 6

If P, Q, R are mid-points of sides of ABC then  4×Area(ΔPQR)=Area(ABC)

Area of  ΔABC=4×12a1 b1c1a2 b2c2a3 b3c32C1C2C3 

Where C1,C2,C3 are cofactors of c1,c2,c3

 ΔABC=4×121-111-232-5112(-1)(3)(-1)

=2×9÷3

=6

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