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Question: Answered & Verified by Expert
Let the sum of an infinite G.P., whose first term is a and the common ratio is r, be 5. Let the sum of its first five terms be 9825. Then the sum of the first 21 terms of an AP, whose first term is 10ar, nth term is an and the common difference is 10ar2, is equal to
MathematicsSequences and SeriesJEE MainJEE Main 2022 (27 Jul Shift 2)
Options:
  • A 21a11
  • B 22a11
  • C 15a16
  • D 14a16
Solution:
1174 Upvotes Verified Answer
The correct answer is: 21a11

For the infinite G.P. 

S=a1-r=5

Also a+ar+ar2+ar3+ar4=5

a1-r51-r=9825

i.e. 1-r5=98125r5=3353r=3535

Now S21=21220ar+21-110ar2

=2110ar+100ar2

=21·a11

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