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Let $z$ be a complex number satisfying $\left|\frac{z-4}{z-8}\right|=1$ and $\left|\frac{z}{z-2}\right|=\frac{3}{2}$
What is $\left|\frac{z-6}{z+6}\right|$ equal to?
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What is $\left|\frac{z-6}{z+6}\right|$ equal to?
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The correct answer is:
0
$\left|\frac{z-6}{z+6}\right|=\left|\frac{6-6}{6+6}\right|=0$
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