Li 7 fuses with a proton according to the nuclear reaction given below: p + 7 L i → 4 H e + 4 H e Given that the atomic masses of 1 H , 4 He and 7 Li are 1 . 007825 u , 4 . 002603 u and 7 . 016004 u respectively, where u = 931 . 5 MeV / c 2 , then the Q - value of the reaction is

Question

Li 7 fuses with a proton according to the nuclear reaction given below: p + 7 L i → 4 H e + 4 H e Given that the atomic masses of 1 H , 4 He and 7 Li are 1 . 007825 u , 4 . 002603 u and 7 . 016004 u respectively, where u = 931 . 5 MeV / c 2 , then the Q - value of the reaction is, 17 . 35 MeV, 18 . 06 MeV, 177 . 35 MeV, 170 . 35 MeV

MARKS App · Accepted Answer

The total mass of the initial particles m i = 1 . 007825 + 7 . 016004 m i = 8 . 023829 u and the total mass of final particles m f = 2 × 4 . 002603 = 8 . 005206 u Difference between the initial and final mass of particles = m i - m f = 8 . 023829 - 8 . 005206 = 0 . 018623 u The Q value is given by Q = ∆ m c 2 = 0 . 018623 × 931 . 5 = 17 . 35 MeV

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