Search any question & find its solution
Question:
Answered & Verified by Expert
Light green crystals of ferrous sulphate lose water molecule and turn brown on exposure to air. This is due to its oxidation to Extra]
Options:
Solution:
2801 Upvotes
Verified Answer
The correct answer is:
$\mathrm{Fe}(\mathrm{OH}) \mathrm{SO}_4$
Light green crystals of ferrous sulphate lose water molecule and turn brown on exposure to air. This is due to its oxidation to \(\mathrm{Fe}(\mathrm{OH}) \mathrm{SO}_4\)
\(\stackrel{+2}{\mathrm{Fe}} \mathrm{SO} \xrightarrow{\mathrm{H}_2 \mathrm{O}} ~\stackrel{+3}{\mathrm{Fe}}(\mathrm{OH}) \mathrm{SO}_4\)
\(\stackrel{+2}{\mathrm{Fe}} \mathrm{SO} \xrightarrow{\mathrm{H}_2 \mathrm{O}} ~\stackrel{+3}{\mathrm{Fe}}(\mathrm{OH}) \mathrm{SO}_4\)
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.