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Light waves producing interference have their amplitudes in the ratio $3: 2$. The intensity ratio of maximum and minimum of interference fringes is
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$25: 1$
Ratio of amplitudes, $\frac{a_1}{a_2}=\frac{3}{2}$
$\therefore \quad \begin{aligned} a_1 & =3 k, a_2=2 k \\ \frac{I_{\max }}{I_{\operatorname{mix}}} & =\frac{\left(a_1+a_2\right)^2}{\left(a_1-a_2\right)^2} \\ & =\frac{(3 k+2 k)^2}{(3 k-2 k)^2}=\frac{25}{1} \\ I_{\operatorname{man}}: I_{\min } & =25: 1\end{aligned}$
$\therefore \quad \begin{aligned} a_1 & =3 k, a_2=2 k \\ \frac{I_{\max }}{I_{\operatorname{mix}}} & =\frac{\left(a_1+a_2\right)^2}{\left(a_1-a_2\right)^2} \\ & =\frac{(3 k+2 k)^2}{(3 k-2 k)^2}=\frac{25}{1} \\ I_{\operatorname{man}}: I_{\min } & =25: 1\end{aligned}$
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