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Question: Answered & Verified by Expert
limt011sin2t+21sin2t+31sin2t......n1sin2tsin2t is equal to
MathematicsLimitsJEE MainJEE Main 2023 (24 Jan Shift 1)
Options:
  • A n2+n
  • B n
  • C nn+12
  • D n2
Solution:
2745 Upvotes Verified Answer
The correct answer is: n

L=limt011sin2t+21sin2t+31sin2t......n1sin2tsin2t

=limt01cosec2t+2cosec2t+3cosec2t......ncosec2tsin2t

=limt0  nsin2tsin2t1ncosec2t+2ncosec2t+3ncosec2t......1sin2t

=nlimt0  0+0+0......10=n

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