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Question: Answered & Verified by Expert
limx1(1-x)1-x21-x2n(1-x)1-x21-xn2=¯,nN
MathematicsLimitsAP EAMCETAP EAMCET 2021 (20 Aug Shift 2)
Options:
  • A Pn2n
  • B Cn2n
  • C (2 n) !
  • D (2n)!n!
Solution:
2055 Upvotes Verified Answer
The correct answer is: Cn2n

limx1(1-x)1-x21-x2n(1-x)1-x21-xn2  nN

limx1(1-x)1-x21-x2n1-x2n(1-x)1-x21-xn21-x2n

limx11-x1-x×1-x21-x.............×1-x2n1-x1-x1-x×1-x21-x×.................×1-xn1-x2

Apply L'hospital rule

limx1-1-1×-2x-1×...........×-2n×x2n-1-1-1-1×-2x-1×................-nxn-1-12

limx11×2×3×..........×2n1×2×3×............n2

=2n!n!2=Cn2n

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