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$\lim _{x \rightarrow-2^{+}}\left([x]^2-[x]-2\right)+\lim _{x \rightarrow-3^{-}}\left([x]^2-4[x]+3\right)=$
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$39$
$\begin{aligned} & \text \quad \lim _{x \rightarrow-2^{+}}\left([-x]^2-[x]-2\right)+\lim _{x \rightarrow-3^{-}}\left([x]^2-4[x]+3\right) \\ & \because \quad \lim _{x \rightarrow-2^{+}}[x]=\lim _{h \rightarrow 0}[-2+h]=-2 \\ & \quad \lim _{x \rightarrow-3^{-}}[x]=\lim _{h \rightarrow 0}[-3-h]=-4 \\ & \Rightarrow(-2)^2-(-2)-2+(-4)^2-4(-4)+3 \\ & =4+2-2+16+16+3=39 .\end{aligned}$
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