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Question: Answered & Verified by Expert
$\lim _{x \rightarrow \pi / 6} \frac{\cot ^2 \theta-3}{\operatorname{cose} \theta-2}=$
MathematicsLimitsJEE Main
Options:
  • A $2$
  • B $4$
  • C $6$
  • D $0$
Solution:
1985 Upvotes Verified Answer
The correct answer is: $4$
$\lim _{x \rightarrow \pi / 6} \frac{\operatorname{cosec}^2 \theta-4}{\operatorname{cosec} \theta-2}=\lim _{x \rightarrow \pi / 6} \operatorname{cosec} \theta+2=4$ \(\left( \text{as, }1+\cot ^2 \theta=\operatorname{cosec}^2 \theta\right)\)

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