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\(\lim _{x \rightarrow 0} \frac{\sin \left(\pi \sin ^2 x\right)}{x^2}=\)
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Verified Answer
The correct answer is:
\(\pi\)
\(\begin{aligned}
& \text {Hints : }=\operatorname{Lt}_{x \rightarrow 0} \frac{\sin \left(\pi \sin ^2 x\right)}{x^2}=\pi_{x \rightarrow 0} \frac{\sin ^2 x}{x^2}=\pi \\
& =\pi
\end{aligned}\)
& \text {Hints : }=\operatorname{Lt}_{x \rightarrow 0} \frac{\sin \left(\pi \sin ^2 x\right)}{x^2}=\pi_{x \rightarrow 0} \frac{\sin ^2 x}{x^2}=\pi \\
& =\pi
\end{aligned}\)
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