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Lithium crystallises into body centered cubic structure. What is the radius of lithium if edge length of it's unit cell is $351 \mathrm{pm}$ ?
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Verified Answer
The correct answer is:
$151.98 \mathrm{pm}$
For bcc unit cell,
$$
r=\frac{\sqrt{3} a}{4}=\frac{\sqrt{3} \times 351}{4}=151.98 \mathrm{pm}
$$
$$
r=\frac{\sqrt{3} a}{4}=\frac{\sqrt{3} \times 351}{4}=151.98 \mathrm{pm}
$$
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