Match list – I with list – II and select the correct answer using the codes given below List – I List – II ( P ) C 6 H 5 – N H 2 → N a N O 2 / H C l 1 . ( Q ) 2 . C H 3 – C H 2 – C H 2 – N ⊕ – N = O ( R ) C H 3 – C H 2 – C H 2 3 – N → N a N O 2 / H C l 3 . C 6 H 5 – N ⊕ = N C l Θ ( S ) 4 .

Question

Match list – I with list – II and select the correct answer using the codes given below List – I List – II ( P ) C 6 H 5 – N H 2 → N a N O 2 / H C l 1 . ( Q ) 2 . C H 3 – C H 2 – C H 2 – N ⊕ – N = O ( R ) C H 3 – C H 2 – C H 2 3 – N → N a N O 2 / H C l 3 . C 6 H 5 – N ⊕ = N C l Θ ( S ) 4 ., P (3), Q (1), R (2), S(4), P (3), Q (1), R (4), S(2), P (1), Q (3), R (4), S(2), P (4), Q (3), R (2), S(1)

MARKS App · Accepted Answer

Here the correct matching is P(3), Q(1), R(2), S(4)

	List – I		List – II
$(P)$	$C_{6} H_{5} - N H_{2} \overset{N a N O_{2} / H C l}{\to}$	$1 .$
$(Q)$		$2 .$	$(C H_{3} - C H_{2} - C H_{2}) - \overset{\oplus}{N} - N = O$
$(R)$	${(C H_{3} - C H_{2} - C H_{2})}_{3} - N \overset{N a N O_{2} / H C l}{\to}$	$3 .$	$C_{6} H_{5} - \overset{\oplus}{N} = N C l^{Θ}$
$(S)$		$4 .$

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