Match the column I with column II and mark the appropriate choice. Column I Column II (p) H 2 g + B r 2 g → 2 H B r g (i) Δ H = Δ U - 2 R T (q) P C l 5 g → P C l 3 g + C l 2 g (ii) Δ H = Δ U + 3 R T (r) N 2 g + 3 H 2 g → 2 N H 3 g (iii) Δ H = Δ U (s) 2 N 2 O 5 g → 4 N O 2 g + O 2 g (iv) Δ H = Δ U + R T

Question

Match the column I with column II and mark the appropriate choice. Column I Column II (p) H 2 g + B r 2 g → 2 H B r g (i) Δ H = Δ U - 2 R T (q) P C l 5 g → P C l 3 g + C l 2 g (ii) Δ H = Δ U + 3 R T (r) N 2 g + 3 H 2 g → 2 N H 3 g (iii) Δ H = Δ U (s) 2 N 2 O 5 g → 4 N O 2 g + O 2 g (iv) Δ H = Δ U + R T, (p)-(iii), (q)-(i), (r)-(ii), (s)-(iv), (p)-(iii), (q)-(iv), (r)-(i), (s)-(ii), (p)-(ii), (q)-(i), (r)-(iv), (s)-(iii), (p)-(iv), (q)-(ii), (r)-(i), (s)-(iii)

MARKS App · Accepted Answer

(p) Δ n g = 2 - 2 = 0 ; hence Δ H = Δ U (q) Δ n g = 2 - 1 = 1 ; hence Δ H = Δ U + R T (r) Δ n g = 2 - 4 = - 2 ; hence Δ H = Δ U - 2 R T (s) Δ n g = 5 - 2 = 3 ; hence Δ H = Δ U + 3 R T

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	Column I		Column II
(p)	$H_{2 (g)} + B r_{2 (g)} \to 2 H B r_{(g)}$	(i)	$Δ H = Δ U - 2 R T$
(q)	$P C l_{5 (g)} \to P C l_{3 (g)} + C l_{2 (g)}$	(ii)	$Δ H = Δ U + 3 R T$
(r)	$N_{2 (g)} + 3 H_{2 (g)} \to 2 N H_{3 (g)}$	(iii)	$Δ H = Δ U$
(s)	$2 N_{2} O_{5 (g)} \to 4 N O_{2 (g)} + O_{2 (g)}$	(iv)	$Δ H = Δ U + R T$