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Match the following :
The correct match is
$\text { A } \quad B \quad C \quad D$
Options:
The correct match is
$\text { A } \quad B \quad C \quad D$
Solution:
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Verified Answer
The correct answer is:
$\begin{array}{llll}\text { II } & \text { III } & \text { IV } & \text { I }\end{array}$
$\mathrm{BF}_3$ has trigonal planar geometry. $\mathrm{B}$ has 3 bond-pairs and 0 lone pair of electrons. $\mathrm{ClF}_3$ has $\mathrm{T}$-shape geometry. $\mathrm{Cl}$ has 3 bond pairs and 2 lone-pairs of electrons. Electronic geometry will be trigonal bipyramidal.
$\mathrm{NH}_3$ has trigonal pyramidal geometry. $\mathrm{N}$ has 3 bond pairs and 1 lone-pair of electrons.
$\mathrm{NH}_4^{+}$has tetrahedral geometry. $\mathrm{N}$ has 4 bond pairs.
Hence, correct match is
$\mathrm{A} \rightarrow \mathrm{II}, \mathrm{B} \rightarrow \mathrm{III}, \mathrm{C} \rightarrow \mathrm{IV}, \mathrm{D} \rightarrow \mathrm{I}$
$\mathrm{NH}_3$ has trigonal pyramidal geometry. $\mathrm{N}$ has 3 bond pairs and 1 lone-pair of electrons.
$\mathrm{NH}_4^{+}$has tetrahedral geometry. $\mathrm{N}$ has 4 bond pairs.
Hence, correct match is
$\mathrm{A} \rightarrow \mathrm{II}, \mathrm{B} \rightarrow \mathrm{III}, \mathrm{C} \rightarrow \mathrm{IV}, \mathrm{D} \rightarrow \mathrm{I}$
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