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Match the measurements given in List I with the number of significant figures given in List II.
$\begin{array}{lll}
\hline & \text{ List I } & \text{ List II } \\
\hline (A) & 74.083 & I. 3 \\
\hline (B) & 0.029 & II. 4 \\
\hline (C) & 0.002407 & III. 2 \\
\hline (D) & 2.74 \times 10^7 & IV. 5 \\
\hline
\end{array}$
The correct answer is
A B C D
Options:
$\begin{array}{lll}
\hline & \text{ List I } & \text{ List II } \\
\hline (A) & 74.083 & I. 3 \\
\hline (B) & 0.029 & II. 4 \\
\hline (C) & 0.002407 & III. 2 \\
\hline (D) & 2.74 \times 10^7 & IV. 5 \\
\hline
\end{array}$
The correct answer is
A B C D
Solution:
1713 Upvotes
Verified Answer
The correct answer is:
V III II I
In 74.083 number of significant figures $=5$
In 0.029 number of significant figures $=2$
In 0.002407 number significant figures $=4$
In $2.47 \times 10^7$ number of significant figures $=3$
In 0.029 number of significant figures $=2$
In 0.002407 number significant figures $=4$
In $2.47 \times 10^7$ number of significant figures $=3$
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