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Question: Answered & Verified by Expert
\( \mathrm{A} \) (Light pink colour complex) \( \frac{\mathrm{Pb}_{3} \mathrm{O}_{4} / \mathrm{dil} . \mathrm{HNO}_{3}}{\Delta} \mathrm{HMnO}_{4} \stackrel{\mathrm{H}_{2} \mathrm{~S} / \mathrm{H}^{+}}{\longrightarrow} \mathrm{A} \) (Light pink colour complex)
Calculate the sum total of CFSE value in light pink colour complex for both sets of orbitals as compared to the average
energy of \( \mathrm{d} \)-orbital.
ChemistryCoordination CompoundsJEE Main
Solution:
1182 Upvotes Verified Answer
The correct answer is: 0
Pink colour complex: [Mn(H2O)6]2+
Mn2+ (3d5) in [Mn(H2O)6]++, Δ 0 < P

CFSE of the pink colour complex = 3 × - 2 5 Δ 0 + 2 × 3 5 Δ 0 = 0

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