$ \mathrm{A} \rightarrow \mathrm{A}^{-}+\mathrm{e}, \mathrm{E}_{1} $ and $ \mathrm{A}^{+} \rightarrow \mathrm{A}^{2+}+\mathrm{e}, \mathrm{E}_{2} $. The energy required to pull out the two electrons are $ \mathrm{E}_{1} $ and $ \mathrm{E}_{2} $ respectively. The correct relationship between two energy would be :

Question

$ \mathrm{A} \rightarrow \mathrm{A}^{-}+\mathrm{e}, \mathrm{E}_{1} $ and $ \mathrm{A}^{+} \rightarrow \mathrm{A}^{2+}+\mathrm{e}, \mathrm{E}_{2} $. The energy required to pull out the two electrons are $ \mathrm{E}_{1} $ and $ \mathrm{E}_{2} $ respectively. The correct relationship between two energy would be :, $ \mathrm{E}_{1} < \mathrm{E}_{2} $, $ \mathrm{E}_{1}>\mathrm{E}_{2} $, $ \mathrm{E}_{1}=\mathrm{E}_{2} $, $ \mathrm{E}_{1} \neq \mathrm{E}_{2} $

MARKS App · Accepted Answer

The second ionization energy is always higher than the first ionization energy as an electron is to be removed from unipositive cation. There is a strong electrostatic attractive force between the unipositive cation and the electron. This makes the removal of electron difficult and requires a large amount of energy. Always I P 2 > I P 1 So E 2 > E 1

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