Search any question & find its solution
Question:
Answered & Verified by Expert
\(\mathrm{X} \mathrm{g}\) of ethylamine is subjected to reaction with \(\mathrm{NaNO}_2 / \mathrm{HCl}\) followed by water; evolved dinitrogen gas which occupied \(2.24 \mathrm{~L}\) volume at STP. \(\mathrm{X}\) is \(\qquad\) \(\times 10^{-1} \mathrm{~g}\).
Solution:
1452 Upvotes
Verified Answer
The correct answer is:
45
$\underset{\substack{\text { Mol.wt.45g }}}{\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2} \xrightarrow{\mathrm{NaNO}_2+\mathrm{HCl}} \xrightarrow{\mathrm{H}_2 \mathrm{O}} \mathrm{CH}_3 \mathrm{CH}_2-\mathrm{OH}+\underset{14 \mathrm{~g}}{\mathrm{~N}_2}$
given : $\mathrm{N}_2$ evolved is 2.24 L i.e. 0.1 mole.
i.e. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$ (ethyl amine) will be $4.5 \mathrm{~g}$
$(=0.1 \mathrm{~mole})$
Hence the answer $=45 \times 10^{-1} \mathrm{~g}$
given : $\mathrm{N}_2$ evolved is 2.24 L i.e. 0.1 mole.
i.e. $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{NH}_2$ (ethyl amine) will be $4.5 \mathrm{~g}$
$(=0.1 \mathrm{~mole})$
Hence the answer $=45 \times 10^{-1} \mathrm{~g}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.