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Maximum value of $Z=5 x+2 y$, subject to $2 x-y \geq 2, x+2 y \leq 8$ and $x, y \geq 0$ is
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Verified Answer
The correct answer is:
$40$
$\mathrm{z}=5 x+2 y$
$\mathrm{z}_{\text {max. }}=5 \times 8+2 \times 0=40$
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