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Metal ' $\mathrm{M}$ ' in the following reaction is
$2 \mathrm{MNO}_3 \rightarrow \mathrm{M}_2 \mathrm{O}+2 \mathrm{NO}_2+\frac{1}{2} \mathrm{O}_2$
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$2 \mathrm{MNO}_3 \rightarrow \mathrm{M}_2 \mathrm{O}+2 \mathrm{NO}_2+\frac{1}{2} \mathrm{O}_2$
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Verified Answer
The correct answer is:
$\mathrm{Li}$
$2 \mathrm{LiNO}_3 \longrightarrow \mathrm{Li}_2 \mathrm{O}+2 \mathrm{NO}_2+\frac{1}{2} \mathrm{O}_2$
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