Molecular weight of oxalic acid is 126. The weight of oxalic acid required to neutralise 100 cc of normal solution of N a O H is

Question

Molecular weight of oxalic acid is 126. The weight of oxalic acid required to neutralise 100 cc of normal solution of N a O H is, 6.3 g m, 126 g m, 530 g m, 63 g m

MARKS App · Accepted Answer

no. of equivalent of acid = no of equivalent of Base ( W e i g h t M o l e c u l a r w e i g h t × ' n ' f a c t o r ) B a s e = ( N × V l i t e r ) A c i d ∴ n factor of NaOH = 1 ∴ n factor of Oxalic acid = 1 1 = x × 1000 63 × 100 x = 6.3 g m s

Search any question & find its solution

Looking for more such questions to practice?