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N2+3H22NH3 

1 mole N2 and 4 moles H2 are taken in 15L flask at 27oC. After complete conversion of N2 into NH3, 5L of H2O is added. Pressure set up in the flask is (assume water dissolves NH3)

ChemistryStates of MatterJEE Main
Options:
  • A 3×0.0821×30015 atm
  • B 2×0.0821×30010 atm
  • C 1×0.0821×30015 atm
  • D 1×0.0821×30010 atm
Solution:
2294 Upvotes Verified Answer
The correct answer is: 1×0.0821×30010 atm
N 2 + 3 H 2 2 NH 3 Initial mole 1 4 0 Reacted mole 1 3   Left mole 0 4-3=1 2

H2 left = 1 mol

NH3 formed = 2 mol

But NH3 g dissolves in water forming NH4OH . Residual gas is only H2 which exerts pressure.

Volume =15-5=10 L (5L occupied by H2O added)

p=nVRT=1×0.0821×30010 atm

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