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Name the end product in the following series of reactions
$\mathrm{CH}_3 \mathrm{COOH} \xrightarrow{\mathrm{NH}_3} A \xrightarrow[\mathrm{P}_2 \mathrm{O}_5]{\Delta} B$
Options:
$\mathrm{CH}_3 \mathrm{COOH} \xrightarrow{\mathrm{NH}_3} A \xrightarrow[\mathrm{P}_2 \mathrm{O}_5]{\Delta} B$
Solution:
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Verified Answer
The correct answer is:
$\mathrm{CH}_4$
$\mathrm{CH}_3 \mathrm{COOH} \xrightarrow{\mathrm{NH}_3} \mathrm{CH}_3 \mathrm{CONH}_2 \xrightarrow[\mathrm{A}_2 \mathrm{O}_5]{\Delta} \mathrm{CH}_3-\mathrm{C} \equiv \mathrm{N}$
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