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Question: Answered & Verified by Expert
Negation of a statement 'If $\forall x, x$ is a complex number then $x^2<0$ ' is
MathematicsMathematical ReasoningMHT CETMHT CET 2022 (05 Aug Shift 2)
Options:
  • A $\exists x, x$ is not a complex number and $x^2 \geq 0$
  • B $\exists x, x$ is not a complex number and $x^2<0$
  • C $\forall x, x$ is not a complex number and $x^2 \geq 0$
  • D $\forall \mathrm{x}, \mathrm{x}$ is not a complex number and $\mathrm{x}^2<0$
Solution:
2027 Upvotes Verified Answer
The correct answer is: $\forall x, x$ is not a complex number and $x^2 \geq 0$
$\because$ Negation of 'if $p$ then $q$ ' is ' $p$ and not q'.
Hence the required negation is
$\forall x, x$ is a complex number and $x^2 \geq 0$

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