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$\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$ on heating liberates a gas. The same gas will be obtained by
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Verified Answer
The correct answer is:
heating $\mathrm{NH}_4 \mathrm{NO}_2$
$\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7$ and $\mathrm{NH}_4 \mathrm{NO}_2$ both on heating liberate nitrogen gas. The reaction involve are as follows
$$
\begin{gathered}
\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7 \stackrel{\Delta \cdot}{\longrightarrow} \mathrm{N}_2 \uparrow+\mathrm{Cr}_2 \mathrm{O}_3+4 \mathrm{H}_2 \mathrm{O} . \\
\mathrm{NH}_4 \mathrm{NO}_3 \longrightarrow \mathrm{N}_2 \mathrm{O}+2 \mathrm{H}_2 \mathrm{O}
\end{gathered}
$$
$$
\begin{gathered}
\left(\mathrm{NH}_4\right)_2 \mathrm{Cr}_2 \mathrm{O}_7 \stackrel{\Delta \cdot}{\longrightarrow} \mathrm{N}_2 \uparrow+\mathrm{Cr}_2 \mathrm{O}_3+4 \mathrm{H}_2 \mathrm{O} . \\
\mathrm{NH}_4 \mathrm{NO}_3 \longrightarrow \mathrm{N}_2 \mathrm{O}+2 \mathrm{H}_2 \mathrm{O}
\end{gathered}
$$
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