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Question: Answered & Verified by Expert
$\mathrm{Ni}(\mathrm{CO})_{4}$ is :
ChemistryCoordination CompoundsKVPYKVPY 2014 (SB/SX)
Options:
  • A tetrahedral and paramagnetic
  • B square planar and diamagnetic
  • C tetrahedral and diamagnetic
  • D square planar and paramagnetic
Solution:
2140 Upvotes Verified Answer
The correct answer is: tetrahedral and diamagnetic
$\quad \mathrm{Ni}(\mathrm{CO})_{4}$ is tetrahedral with $\mathrm{d}^{10}$ configuration

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