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Number of electrons flowing per second in a conductor carrying a current of $9 \mathrm{~A}$ is
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Verified Answer
The correct answer is:
$5.6 \times 10^{19}$
Given that, electric current, $I=9 \mathrm{~A}$
Let $n$ be the number of electron passing through a conductor in time $t$.
We know that, $I=\frac{q}{t}$ and
$$
q=n e
$$
$$
\begin{aligned}
& \therefore & I=\frac{n e}{t} \\
\Rightarrow & \frac{n}{t} & =\frac{I}{e}
\end{aligned}
$$
Substituting the values, we get
Number of electron flowing per second, $\frac{n}{t}=\frac{9}{1.6 \times 10^{-19}}=5.6 \times 10^{19}$ electrons per second.
Let $n$ be the number of electron passing through a conductor in time $t$.
We know that, $I=\frac{q}{t}$ and
$$
q=n e
$$
$$
\begin{aligned}
& \therefore & I=\frac{n e}{t} \\
\Rightarrow & \frac{n}{t} & =\frac{I}{e}
\end{aligned}
$$
Substituting the values, we get
Number of electron flowing per second, $\frac{n}{t}=\frac{9}{1.6 \times 10^{-19}}=5.6 \times 10^{19}$ electrons per second.
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