Number of moles of K 2 C r 2 O 7 that can be reduced by 1 mol of S n 2 + ions is

Question

Number of moles of K 2 C r 2 O 7 that can be reduced by 1 mol of S n 2 + ions is, 1 3, 3 2, 5 6, 6 5

MARKS App · Accepted Answer

C r 2 O 7 2 - + 14 H + + 3 S n 2 + → 2 C r 3 + + 7 H 2 O + 3 S n 4 + As 1 mole of K 2 C r 2 O 7 is oxidising 3 moles of S n 2 + So 1 m o l S n 2 + ≡ 1 3 m o l o f C r 2 O 7 2 - .

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