$(2 x-3 y)^{11}=(2 x)^{11}\left(1-\frac{3 y}{2 x}\right)^{11}$ for greatest term
$$
\begin{aligned}
& \frac{(\mathrm{n}+1)|\mathrm{x}|}{|\mathrm{x}|+1} \text { for }(1+\mathrm{x})^{\mathrm{n}} \\
&= \frac{(11+1)\left|\frac{-3 \mathrm{y}}{2 \mathrm{x}}\right|}{\left|\frac{-3 \mathrm{y}}{2 \mathrm{x}}\right|+1} \text {. Put } \mathrm{x}=\frac{1}{3} \text { and } \mathrm{y}=\frac{1}{2} \\
&= \frac{12 \times \frac{9}{4}}{\frac{9}{4}+1}=\frac{108}{13}=8.30 \\
& \therefore(8+1)^{\text {th }} \text { i.e., } 9^{\text {th }} \text { is greatest term } \\
& \mathrm{T}_9=\mathrm{T}_8+1={ }^{11} \mathrm{C}_8(2 \mathrm{x})^{11}\left(\frac{-3 \mathrm{y}}{2 \mathrm{x}}\right)^8 \\
&={ }^{11} \mathrm{C}_3\left(\frac{2}{3}\right)^{11}\left(\frac{9}{4}\right)^8 \\
&={ }^{11} \mathrm{C}_3\left(\frac{2}{3}\right)^{-11}\left(\frac{3}{2}\right)^{16} \\
&={ }^{11} \mathrm{C}_3\left(\frac{3}{2}\right)^5
\end{aligned}
$$