Search any question & find its solution
Question:
Answered & Verified by Expert
Observe the following reaction
$\begin{aligned} & \text { a } \mathrm{P}_4(\mathrm{~s})+\mathrm{b}^{-} \mathrm{OH}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \\ & \qquad \mathrm{cPH}_3(\mathrm{~g})+\mathrm{dH}_2 \mathrm{PO}_2^{-}(\mathrm{aq})\end{aligned}$
$\mathrm{a}, \mathrm{b}, \mathrm{c}$ and $\mathrm{d}$ are respectively
Options:
$\begin{aligned} & \text { a } \mathrm{P}_4(\mathrm{~s})+\mathrm{b}^{-} \mathrm{OH}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \\ & \qquad \mathrm{cPH}_3(\mathrm{~g})+\mathrm{dH}_2 \mathrm{PO}_2^{-}(\mathrm{aq})\end{aligned}$
$\mathrm{a}, \mathrm{b}, \mathrm{c}$ and $\mathrm{d}$ are respectively
Solution:
2468 Upvotes
Verified Answer
The correct answer is:
$1,3,1,3$
The balanced equation is :-
$\mathrm{P}_4(\mathrm{~s})+3 \mathrm{OH}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{PH}_3(\mathrm{~g})+3 \mathrm{H}_2 \mathrm{PO}_2^{-}$(aq.)
Thus, $a=1, b=3, c=1$ and $d=3$
$\mathrm{P}_4(\mathrm{~s})+3 \mathrm{OH}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{PH}_3(\mathrm{~g})+3 \mathrm{H}_2 \mathrm{PO}_2^{-}$(aq.)
Thus, $a=1, b=3, c=1$ and $d=3$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.