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Question: Answered & Verified by Expert
Observe the graph of area versus species richness and select the options that explain lines 1 and 2.
BiologyBiodiversity and its ConservationNEET
Options:
  • A 1 - Molluscs in New York State and 2 - plants in Britain
  • B 1 - plants in Britain and 2 - birds in California
  • C 1 - frugivorous birds and mammals in the tropical forests of different continents and 2 - plants in Britain
  • D 1 - Molluscs in New York state and 2 - frugivorous birds and mammals in the tropical forests of different continents
Solution:
1426 Upvotes Verified Answer
The correct answer is: 1 - Molluscs in New York state and 2 - frugivorous birds and mammals in the tropical forests of different continents
Alexander von Humboldt observed that within a region species richness increased with increasing explored area, but only up to a limit. In fact, the relation between species richness and area for a wide variety of taxa turns out to be a rectangular hyperbola. On a logarithmic scale, the relationship is a straight line described by the equation log S =  log C + Z log A where S= Species richness A= Area Z = slope of the line (regression coefficient) C = Y- intercept Ecologists have discovered that the value of Z lies in the range of 0.1 to 0.2 , regardless of the taxonomic group or the region (whether it is the plants in Britain, birds in California or molluscs in New York state). But, if you analyse the species-area relationships among very large areas like the entire continents, you will find that the slope of the line to be much steeper. For example, for frugivorous (fruit-eating) birds and mammals in the tropical forests of different continents, the slope is found to be 1.15 . In this graph line 2 is steeper than line 1 . Thus Z value is higher.

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