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Question:
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Of the following reactions
(i) $\mathrm{A} \rightleftharpoons \mathrm{B} \quad \Delta \mathrm{G}^{\circ}=250 \mathrm{~kJ} \mathrm{~mol}^{-1}$
(ii) $\mathrm{D} \rightleftharpoons \mathrm{E} \quad \Delta \mathrm{G}^{\circ}=-100 \mathrm{~kJ} \mathrm{~mol}^{-1}$
(iii) $\mathrm{F} \rightleftharpoons \mathrm{G} \quad \Delta \mathrm{G}^{\circ}=-150 \mathrm{~kJ} \mathrm{~mol}^{-1}$
(iv) $\mathrm{M}=\mathrm{N} \quad \Delta \mathrm{G}^{\circ}=150 \mathrm{~kJ} \mathrm{~mol}^{-1}$
Options:
(i) $\mathrm{A} \rightleftharpoons \mathrm{B} \quad \Delta \mathrm{G}^{\circ}=250 \mathrm{~kJ} \mathrm{~mol}^{-1}$
(ii) $\mathrm{D} \rightleftharpoons \mathrm{E} \quad \Delta \mathrm{G}^{\circ}=-100 \mathrm{~kJ} \mathrm{~mol}^{-1}$
(iii) $\mathrm{F} \rightleftharpoons \mathrm{G} \quad \Delta \mathrm{G}^{\circ}=-150 \mathrm{~kJ} \mathrm{~mol}^{-1}$
(iv) $\mathrm{M}=\mathrm{N} \quad \Delta \mathrm{G}^{\circ}=150 \mathrm{~kJ} \mathrm{~mol}^{-1}$
Solution:
2919 Upvotes
Verified Answer
The correct answer is:
(iii)
$\Delta G^{\circ}=-R T \ln K_{e q}$
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