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Question: Answered & Verified by Expert
On heating, chloric acid decomposes to
Chemistryp Block Elements (Group 15, 16, 17 & 18)WBJEEWBJEE 2013
Options:
  • A $\mathrm{HClO}_{4} . \mathrm{Cl}_{2}, \mathrm{O}_{2}$ and $\mathrm{H}_{2} \mathrm{O}$
  • B $\mathrm{HClO}_{2}$, $\mathrm{Cl}_{2}, \mathrm{O}_{2}$ and $\mathrm{H}_{2} \mathrm{O}$
  • C $\mathrm{HClO}, \mathrm{Cl}_{2} \mathrm{O}$ and $\mathrm{H}_{2} \mathrm{O}_{2}$
  • D $\mathrm{HCl}, \mathrm{HClO}, \mathrm{Cl}_{2} \mathrm{O},$ and $\mathrm{H}_{2} \mathrm{O}$
Solution:
1436 Upvotes Verified Answer
The correct answer is: $\mathrm{HClO}_{4} . \mathrm{Cl}_{2}, \mathrm{O}_{2}$ and $\mathrm{H}_{2} \mathrm{O}$
$3 \mathrm{HClO}_{3} \stackrel{\mathrm{\Delta}}{\longrightarrow} \mathrm{HClO}_{4}+\mathrm{Cl}_{2}+2 \mathrm{O}_{2}+\mathrm{H}_{2} \mathrm{O}$

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