On reduction with hydrogen, 3.6 g of an oxide of metal left 3.2 g of metal. If the atomic weight of metal is 64, the simplest formula of the oxide is

Question

On reduction with hydrogen, 3.6 g of an oxide of metal left 3.2 g of metal. If the atomic weight of metal is 64, the simplest formula of the oxide is, MO, M 2 O 3, M 2 O, M 2 O 5

MARKS App · Accepted Answer

Let the metal oxide by M x O y M x O y + y H 2 → x M + y H 2 O Moles of metal = 3.2 64 = 0.05 Moles of metal oxides = 3.6 64 x + 16 y 1 mole of metal oxides gives x mole metal M 0.05 x = 3.6 64 x + 16 y 64 x + 16 y = 72 x 8 x = 16 y x = 2 y Simplest formula is for x = 2, y = 1 The formula is M 2 O

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