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Question: Answered & Verified by Expert
On the basis of information given below mark the correct option. Information:
(A) In bromoethane and chloroethane mixture intermolecular interactions of \( \mathrm{A}-\mathrm{A} \) and \( \mathrm{B}-\mathrm{B} \) type are nearly same as
\( \mathrm{A}-\mathrm{B} \) type interactions.
(B) In ethanol and acetone mixture, \( \mathrm{A}-\mathrm{A} \) or \( \mathrm{B}-\mathrm{B} \) type intermolecular interactions are stronger than \( \mathrm{A}-\mathrm{B} \) type
interactions.
(C) In chloroform and acetone mixture, \( \mathrm{A}-\mathrm{A} \) or \( \mathrm{B}-\mathrm{B} \) type intermolecular interactions are weaker than \( \mathrm{A}-\mathrm{B} \) type
interactions.
ChemistrySolutionsJEE Main
Options:
  • A Solution (B) and (C) will follow Raoult's law.
  • B Solution (A) will follow Raoult's law.
  • C Solution (B) will show negative deviation from Raoult's law.
  • D Solution (C) will show positive deviation from Raoult's law.
Solution:
2754 Upvotes Verified Answer
The correct answer is: Solution (A) will follow Raoult's law.

Each constituent of a binary liquid solution will obey Rault's law if the A-A and B-B forces of attraction are more or less the same as the A-B force of attraction. In such a case, the total vapour pressure of the solution is the sum of the partial vapour pressures of components of the solution.

The bromoethane and chloroethane mixture follows the Raoult's law because the intermolecular interactions of A-A and B-B type are nearly the same as A-B type interactions.

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