Search any question & find its solution
Question:
Answered & Verified by Expert
One mole of a gas at a pressure $2 \mathrm{~Pa}$ and temperature $27^{\circ} \mathrm{C}$ is heated till both pressure and volume are doubled. What is the temperature of the gas?
Options:
Solution:
2887 Upvotes
Verified Answer
The correct answer is:
$1200 \mathrm{~K}$
Given,
Let volume, $V_1=V$
By using ideal gas equation,
$\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}$
Substituting the values, we get
$\frac{2 V}{300}=\frac{4(2 V)}{T} \Rightarrow T=1200 \mathrm{~K}$
Let volume, $V_1=V$
By using ideal gas equation,
$\frac{p_1 V_1}{T_1}=\frac{p_2 V_2}{T_2}$
Substituting the values, we get
$\frac{2 V}{300}=\frac{4(2 V)}{T} \Rightarrow T=1200 \mathrm{~K}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.