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One mole of an ideal gas performs $900 \mathrm{~J}$ of work on surrounding. If internal energy increases by $625 \mathrm{~J}$, find the value of $\Delta \mathrm{H}$.
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$1525 \mathrm{~J}$
$\begin{array}{ll} & \mathrm{W}=-900 \mathrm{~J}, \Delta \mathrm{U}=+625 \mathrm{~J} \\ & \text { Assuming constant pressure, } \\ & \Delta \mathrm{H}=\Delta \mathrm{U}+\mathrm{P}_{\mathrm{ext}} \Delta \mathrm{V} \\ \therefore \quad & \Delta \mathrm{H}=\Delta \mathrm{U}-\mathrm{W} \\ \therefore \quad & \Delta \mathrm{H}=+625-(-900)=1525 \mathrm{~J}\end{array}$
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