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One solid sphere A and another hollow sphere B are of same mass and same outer radii. Their moment of inertia about their diameters are respectively $\mathrm{I}_{\mathrm{A}}$ and $\mathrm{I}_{\mathrm{B}}$ such that
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The correct answer is:
$I_A < I_B$
$I_A < I_B$
Moment of inertia of a uniform density solid sphere, $A=\frac{2}{5} M R^2$
Since $M$ and $R$ are same, $I_A < I_B$.
Since $M$ and $R$ are same, $I_A < I_B$.
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