Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Oxidation of toluene with $\mathrm{CrO}_3$ in the presence of $\left(\mathrm{CH}_3 \mathrm{CO}\right) \mathrm{O}_2$ gives a product ' $A$ ' which on treatment with aqueous $\mathrm{NaOH}$ produces
ChemistryCarboxylic Acid DerivativesJEE Main
Options:
  • A $\mathrm{C}_6 \mathrm{H}_3 \mathrm{CHO}$
  • B $\left(\mathrm{C}_6 \mathrm{H}_3 \mathrm{CO}\right)_2 \mathrm{O}$
  • C $\mathrm{C}_6 \mathrm{H}_3 \mathrm{COONa}$
  • D 2, 4-diacetyl toluene
Solution:
2744 Upvotes Verified Answer
The correct answer is: $\mathrm{C}_6 \mathrm{H}_3 \mathrm{COONa}$


Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.