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Oxidation state of iodine in $\mathrm{I}_3^{-}$is
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1266 Upvotes
Verified Answer
The correct answer is:
$-(1 / 3)$
$\mathrm{I}_3^{-}$
$\downarrow$
$\mathrm{x}$ (let oxidation state of iodine)
$$
3 x=-1
$$
$$
x=-1 / 3
$$
$\downarrow$
$\mathrm{x}$ (let oxidation state of iodine)
$$
3 x=-1
$$
$$
x=-1 / 3
$$
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