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Oxidation state of manganese in potassium permanganate is:
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$+7$
Oxidation number of $\mathrm{K}=+1$
Oxidation number of $\mathrm{O}=-2$
$\mathrm{KMnO}_4$ is a neutral molecule.
$\therefore \quad$ Sum of the oxidation number of all atoms $=0$
Oxidation number of $\mathrm{K}+$ Oxidation number of $\mathrm{Mn}+4 \times($ Oxidation number of $\mathrm{O})=0$
$(+1)+($ Oxidation number of $\mathrm{Mn})+4 \times(-2)=0$
$1+($ Oxidation number of $\mathrm{Mn})=+8$
$\therefore \quad$ Oxidation number of $\mathrm{Mn}=+7$
Oxidation number of $\mathrm{O}=-2$
$\mathrm{KMnO}_4$ is a neutral molecule.
$\therefore \quad$ Sum of the oxidation number of all atoms $=0$
Oxidation number of $\mathrm{K}+$ Oxidation number of $\mathrm{Mn}+4 \times($ Oxidation number of $\mathrm{O})=0$
$(+1)+($ Oxidation number of $\mathrm{Mn})+4 \times(-2)=0$
$1+($ Oxidation number of $\mathrm{Mn})=+8$
$\therefore \quad$ Oxidation number of $\mathrm{Mn}=+7$
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